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Proof step 6 from proof byte-equal (previous step)

i2b(b2i(byj)) = byj, i2b(b2i(byi)) = byi, b2i(byi) = b2i(byj) ⊦ byi = byj

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 3 flags: discard

Additional information