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Proof step 30 from proof byte-law-and-one (previous step)

lastn(8, fillsgn(8, sgn(bitsand(int2bits(i), int2bits(j))))) ≠ [] ∧ lastn(8, fillsgn(8, sgn(bitsand(lastn(8, fillsgn(8, int2bits(i))), int2bits(j))))) ≠ [], bitsand(int2bits(i), int2bits(j)) ≠ [], lastn(8, fillsgn(8, int2bits(i))) ≠ [] ∧ int2bits(j) ≠ [], bitsand(sgn(lastn(8, fillsgn(8, int2bits(i)))), int2bits(j)) ≠ [], lastn(8, fillsgn(8, int2bits(i))) ≠ [] ⊦ bits2int(bitsand(int2bits(i), int2bits(j))) = bits2int(bitsand(sgn(lastn(8, fillsgn(8, int2bits(i)))), int2bits(j))), sgn(lastn(8, fillsgn(8, sgn(bitsand(int2bits(i), int2bits(j)))))) = sgn(lastn(8, fillsgn(8, sgn(bitsand(lastn(8, fillsgn(8, int2bits(i))), int2bits(j))))))

User applied rule weakening

And obtained the following new goals

Rule argument

poslist: left 1, left 2, left 3, left 4, left 5, right 1

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