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Proof step 31 from proof byte-law-and-one (previous step)

⊦ sgn(lastn(8, fillsgn(8, sgn(bitsand(int2bits(i), int2bits(j)))))) = sgn(lastn(8, fillsgn(8, sgn(bitsand(lastn(8, fillsgn(8, int2bits(i))), int2bits(j))))))

User applied rule cut formula

And obtained the following new goals

Proof step 32:
⊦ lastn(8, fillsgn(8, sgn(bitsand(int2bits(i), int2bits(j))))) = lastn(8, fillsgn(8, sgn(bitsand(lastn(8, fillsgn(8, int2bits(i))), int2bits(j))))), sgn(lastn(8, fillsgn(8, sgn(bitsand(int2bits(i), int2bits(j)))))) = sgn(lastn(8, fillsgn(8, sgn(bitsand(lastn(8, fillsgn(8, int2bits(i))), int2bits(j))))))

Rule argument

fma: lastn(8, fillsgn(8, sgn(bitsand(int2bits(i), int2bits(j))))) = lastn (8, fillsgn (8, sgn(bitsand(lastn(8, fillsgn(8, int2bits(i))), int2bits(j)))))

Additional information

Used formulas: lastn(8, fillsgn(8, sgn(bitsand(int2bits(i), int2bits(j))))) = lastn (8, fillsgn (8, sgn(bitsand(lastn(8, fillsgn(8, int2bits(i))), int2bits(j)))))