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Proof step 13 from proof byte-law-mult-one (previous step)

i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0, ~128 ≤ j0 ⊦ j0 = 0, i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i

Rule argument

name: bib-in-01 rotate: F subst: [i] → [j0]

Additional information

Used simplifier rules: ⊦ i * j = j * i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i; Used terms: j0