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Proof step 12 from proof byte-law-mult-one (previous step)

¬(~256 < j0 ∧ j0 < ~128), ~256 < j0, i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0 ⊦ j0 = 0, i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0, ~128 ≤ j0 ⊦ j0 = 0, i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)%i0 ≠ 0, i0 < i ⊦ (* i) ≤ j → (* i0) < j;% ⊦ ¬ i < j ↔ j ≤ i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j;