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Proof step 10 from proof byte-law-mult-one (previous step)

~256 < j0, i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0 ⊦ j0 = 0, i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ ~256 < i ∧ i < ~128 → b2i(i2b(i)) = i + 256
Proof step 12:
¬(~256 < j0 ∧ j0 < ~128), ~256 < j0, i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0 ⊦ j0 = 0, i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)
Proof step 15:
~256 < j0 ∧ j0 < ~128, ~256 < j0, i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0 ⊦ j0 = 0, i2b(j0 * j) = i2b((j0 + 256) * j)

Rule argument

name: bib-lower rotate: F subst: [i] → [j0]

Additional information

Used terms: j0