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Proof step 9 from proof byte-law-mult-one (previous step)

~256 < j0, i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0 ⊦ j0 = 0, i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information