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Proof step 7 from proof byte-law-mult-one (previous step)

~256 < j0, i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0 ⊦ j0 = 0, i2b((i0 * j) * 256 + j0 * j) = i2b(b2i(i2b(j0)) * j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i2b(i * 256 + j) = i2b(j)
Proof step 9:
~256 < j0, i0 ≤ 0, i0 * 256 + j0 < 0, j0 < 0 ⊦ j0 = 0, i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)

Rule argument

name: byte-mult-256 rotate: F subst: [j, i] → [j0 * j, i0 * j]

Additional information

Used terms: j0 * j, i0 * j