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Proof step 17 from proof byte-law-mult-one (previous step)

(j0 + 256) * j = j * 256 + j0 * j, j0 < 0, i0 * 256 + j0 < 0, i0 ≤ 0, ~256 < j0, j0 < ~128 ⊦ i2b(j0 * j) = i2b((j0 + 256) * j), j0 = 0

User applied rule insert equation

And obtained the following new goals

Proof step 18:
j0 < 0, i0 * 256 + j0 < 0, i0 ≤ 0, ~256 < j0, j0 < ~128 ⊦ i2b(j0 * j) = i2b(j * 256 + j0 * j), j0 = 0

Rule argument

pos: left 1 flags: discard

Additional information