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Proof step 18 from proof byte-law-mult-one (previous step)

j0 < 0, i0 * 256 + j0 < 0, i0 ≤ 0, ~256 < j0, j0 < ~128 ⊦ i2b(j0 * j) = i2b(j * 256 + j0 * j), j0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: byte-mult-256 rotate: F subst: [j, i] → [j0 * j, j]

Additional information

Used terms: j0 * j, j