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Proof step 27 from proof byte-law-mult-one (previous step)

(i0 * 256 + j0) * j = (i0 * j) * 256 + j0 * j, j0 < 256, 0 ≤ i0, 0 ≤ j0 ⊦ i2b((i0 * 256 + j0) * j) = i2b(b2i(i2b(j0)) * j)

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information