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Proof step 28 from proof byte-law-mult-one (previous step)

j0 < 256, 0 ≤ i0, 0 ≤ j0 ⊦ i2b((i0 * j) * 256 + j0 * j) = i2b(b2i(i2b(j0)) * j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 29:
⊦ i2b(i * 256 + j) = i2b(j)
Proof step 30:
j0 < 256, 0 ≤ i0, 0 ≤ j0 ⊦ i2b(j0 * j) = i2b(b2i(i2b(j0)) * j)

Rule argument

name: byte-mult-256 rotate: F subst: [j, i] → [j0 * j, i0 * j]

Additional information

Used terms: j0 * j, i0 * j