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Proof step 35 from proof byte-law-mult-one (previous step)

(j0 - 256) * j = ~ j * 256 + j * j0, 0 < j0, 0 ≤ j0, 0 ≤ i0, j0 < 256, 127 < j0 ⊦ i2b(j0 * j) = i2b((j0 - 256) * j)

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information