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Proof step 36 from proof byte-law-mult-one (previous step)

0 < j0, 0 ≤ j0, 0 ≤ i0, j0 < 256, 127 < j0 ⊦ i2b(j0 * j) = i2b(~ j * 256 + j * j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: byte-mult-256 rotate: F subst: [j, i] → [j * j0, ~ j]

Additional information

Used simplifier rules: ⊦ i * j = j * i; Used terms: j * j0, ~ j