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Proof step 39 from proof byte-law-neg (previous step)

¬(0 ≤ i ∧ 127 < i % 256), 0 < i, 0 ≤ i, 127 < i ⊦ i2b(~ i) = i2b(~ b2i(i2b(i)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
0 < i, 0 ≤ i, 127 < i, i % 256 ≤ 127, i % 256 < i ⊦ i2b(~ i) = i2b(~(i % 256))

Rule argument

Additional information

Used simplifier rules: bib-pos-low: ⊦ 0 ≤ i ∧ i % 256 ≤ 127 → b2i(i2b(i)) = i % 256;% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → ¬ j < i;% ⊦ ¬ i ≤ j ↔ j < i;