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Proof step 40 from proof byte-law-neg (previous step)

0 < i, 0 ≤ i, 127 < i, i % 256 ≤ 127, i % 256 < i ⊦ i2b(~ i) = i2b(~(i % 256))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 41:
⊦ i2b(i) = i2b(j) ↔ b2i(i2b(i)) = b2i(i2b(j))
Proof step 42:
0 < i, 0 ≤ i, 127 < i, i % 256 ≤ 127, i % 256 < i ⊦ b2i(i2b(~ i)) = b2i(i2b(~(i % 256)))

Rule argument

name: i2b-equal rotate: F subst: [j, i] → [~(i % 256), ~ i]

Additional information

Used terms: ~(i % 256), ~ i