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Proof step 52 from proof byte-law-neg (previous step)

i % 256 = 128, 127 < i, 0 < i ⊦ 0 = i, i2b(~ i) = i2b(128)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 53:
⊦ i2b(i) = i2b(j) ↔ b2i(i2b(i)) = b2i(i2b(j))
Proof step 54:
i % 256 = 128, 127 < i, 0 < i ⊦ 0 = i, b2i(i2b(~ i)) = b2i(i2b(128))

Rule argument

name: i2b-equal rotate: F subst: [j, i] → [128, ~ i]

Additional information

Used terms: 128, ~ i