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Proof step 54 from proof byte-law-neg (previous step)

i % 256 = 128, 127 < i, 0 < i ⊦ 0 = i, b2i(i2b(~ i)) = b2i(i2b(128))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 55:
⊦ 127 < i ∧ i < 256 → b2i(i2b(i)) = i - 256
Proof step 56:
127 < 128 ∧ 128 < 256, i % 256 = 128, 127 < i, 0 < i ⊦ 0 = i, b2i(i2b(~ i)) = 128 - 256

Rule argument

name: bib-upper rotate: F subst: [i] → [128]

Additional information

Used simplifier rules: bib-upper: ⊦ 127 < i ∧ i < 256 → b2i(i2b(i)) = i - 256; Used terms: 128