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Proof step 17 from proof byte-law-righthift-not (previous step)

~128 < 0, i2b(0) = i2b(bits2int(sublist(0, n, sgn(bitsinvert(uint2bits(abs(~128))) +1)))), # sgn(bitsinvert(uint2bits(abs(~128))) +1) = n + i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), # int2bits(128) ≤ i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) < # sgn(bitsinvert(uint2bits(abs(~128))) +1), # int2bits(128) < # sgn(bitsinvert(uint2bits(abs(~128))) +1) ⊦ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward)% ⊦ m < n → n ≠ 0; (forward)% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ sgn(true ' + false ' + bits) = true ' + false ' + bits;% ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);% ⊦ (bits + false ')+1 = bits + true;% ⊦ (bits + true ')+1 = bits +1 + false;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar + bits = boolvar ' + bits;% ⊦ bitsinvert(false ') = true ';% ⊦ bitsinvert(true ' + bits) = false + bitsinvert(bits);% ⊦ bitsinvert(false ' + bits) = true + bitsinvert(bits);% ⊦ bits + boolvar = bits + boolvar ';% ⊦ boolvar + boolvar0 = boolvar ' + boolvar0 ';% ⊦ uint2bits(1) = false + true;%1 < i ⊦ uint2bits((* i)) = uint2bits(i / 2) + (i % 2 = 1);