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Proof step 18 from proof byte-law-righthift-not (previous step)

8 = n + i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), i2b(0) = i2b(bits2int(sublist(0, n, true ' + false ' + false ' + false ' + false ' + false ' + false ' + false '))), # int2bits(128) < 8, i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) < 8, # int2bits(128) ≤ i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) ⊦ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ i → int2bits(i) = uint2bits(i) subst: [i] → [128] rotate: F spec: int2bits inst: name: int2bits-pos

Additional information

Used simplifier rules: 1 < i ⊦ uint2bits((* i)) = uint2bits(i / 2) + (i % 2 = 1);% ⊦ uint2bits(1) = false + true;% ⊦ boolvar + boolvar0 = boolvar ' + boolvar0 ';% ⊦ bits + boolvar = bits + boolvar ';% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ # boolvar ' = 0 +1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: 128