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Proof step 27 from proof byte-mult-256 (previous step)

¬(~128 ≤ j0 ∧ j0 ≤ 127), ~256 ≤ j0, 0 < i, ~256 < j0, j0 < 0 ⊦ i = 0, b2i(i2b(256 + j0)) = b2i(i2b(j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 28:
⊦ ~256 < i ∧ i < ~128 → b2i(i2b(i)) = i + 256
Proof step 29:
~256 < j0 ∧ j0 < ~128, ¬(~128 ≤ j0 ∧ j0 ≤ 127), ~256 ≤ j0, 0 < i, ~256 < j0, j0 < 0 ⊦ i = 0, b2i(i2b(256 + j0)) = j0 + 256

Rule argument

name: bib-lower rotate: F subst: [i] → [j0]

Additional information

Used simplifier rules: byte-equal: ⊦ b2i(byi) = b2i(byj) ↔ byi = byj;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j;%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0); Used terms: j0