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Proof step 29 from proof byte-mult-256 (previous step)

~256 < j0 ∧ j0 < ~128, ¬(~128 ≤ j0 ∧ j0 ≤ 127), ~256 ≤ j0, 0 < i, ~256 < j0, j0 < 0 ⊦ i = 0, b2i(i2b(256 + j0)) = j0 + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 30:
⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i
Proof step 31:
¬(~128 ≤ 256 + j0 ∧ 256 + j0 ≤ 127), ~256 < j0 ∧ j0 < ~128, ¬(~128 ≤ j0 ∧ j0 ≤ 127), ~256 ≤ j0, 0 < i, ~256 < j0, j0 < 0 ⊦ i = 0, b2i(i2b(256 + j0)) = j0 + 256

Rule argument

name: bib-in-01 rotate: F subst: [i] → [256 + j0]

Additional information

Used simplifier rules: ⊦ i + j = j + i; Used terms: 256 + j0