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Proof step 31 from proof byte-mult-256 (previous step)

¬(~128 ≤ 256 + j0 ∧ 256 + j0 ≤ 127), ~256 < j0 ∧ j0 < ~128, ¬(~128 ≤ j0 ∧ j0 ≤ 127), ~256 ≤ j0, 0 < i, ~256 < j0, j0 < 0 ⊦ i = 0, b2i(i2b(256 + j0)) = j0 + 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
j0 < ~128, ~256 ≤ j0, 0 < i, j0 < 0, ~129 < j0 ⊦ i = 0, b2i(i2b(256 + j0)) = j0 + 256

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i + (* j) ≤ (* j0) ↔ i ≤ j0 - j;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ ¬ i ≤ j ↔ j < i;