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Proof step 32 from proof byte-mult-256 (previous step)

j0 < ~128, ~256 ≤ j0, 0 < i, j0 < 0, ~129 < j0 ⊦ i = 0, b2i(i2b(256 + j0)) = j0 + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 33:
⊦ i < j ↔ i +1 = j ∨ i +1 < j

Rule argument

seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [~128, j0] rotate: F spec: int-basic1 inst: name: lsrec

Additional information

Used simplifier rules: num-ibbi: ~128 ≤ i, i ≤ 127 ⊦ b2i(i2b((* i))) = i;% ⊦ i +1 = i + 1;% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ i < j → ¬ j < i; Used terms: ~128, j0