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Proof step 2 from proof byte-nge (previous step)

i ≥ 128 ⊦ ¬ i ≤ b2i(by)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
128 ≤ b2i(by), 0 ≤ i, 0 < i, 128 ≤ i, i ≤ b2i(by), 0 < b2i(by), 0 ≤ b2i(by) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i ≥ j ↔ ¬ i < j;