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Proof step 3 from proof byte-nge (previous step)

128 ≤ b2i(by), 0 ≤ i, 0 < i, 128 ≤ i, i ≤ b2i(by), 0 < b2i(by), 0 ≤ b2i(by) ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
i ≥ 127 ⊦ ¬ (* i) < b2i(by)

Rule argument

name: byte-ngr subst: [i, by] → [b2i(by) -1, by]

Additional information

Used simplifier rules: ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ i ≥ j ↔ ¬ i < j;% ⊦ i -1 = i - 1;% ⊦ i - j < i0 ↔ i < j + i0;% ⊦ i < j + 1 ↔ i ≤ j;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ i < i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: b2i(by) -1, by