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Proof step 11 from proof byte-not-max (previous step)

0 < i, 0 < b2i(by), 126 < b2i(by), 126 = b2i(by) + i ∨ b2i(by) + i < 126 ⊦ b2i(by) + i = 127

User applied rule case distinction

And obtained the following new goals

Proof step 12:
126 = b2i(by) + i, 0 < i, 0 < b2i(by), 126 < b2i(by) ⊦ b2i(by) + i = 127
Proof step 14:
b2i(by) + i < 126, 0 < i, 0 < b2i(by), 126 < b2i(by) ⊦ b2i(by) + i = 127

Rule argument

pos: left 4

Additional information