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Proof step 14 from proof byte-not-max (previous step)

b2i(by) + i < 126, 0 < i, 0 < b2i(by), 126 < b2i(by) ⊦ b2i(by) + i = 127

User applied rule cut formula

And closed the goal!

Rule argument

fma: b2i(by) + i < b2i(by)

Additional information

Used simplifier rules: ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ i + j < j ↔ i < 0;% ⊦ i < j → ¬ j < i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used formulas: b2i(by) + i < b2i(by)