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Proof step 1 from proof div-inshort (conclusion)

⊦ s2i(sho1) ≠ 0 → ((s2i(sho0) / s2i(sho1))∈short ↔ ¬(s2i(sho1) = ~1 ∧ s2i(sho0) = ~32768))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ s2i(sho1) = 0, ~32768 ≤ s2i(sho0) / s2i(sho1) ∧ s2i(sho0) / s2i(sho1) ≤ 32767 ↔ s2i(sho1) ≠ ~1 ∨ s2i(sho0) ≠ ~32768

Rule argument

Additional information

Used simplifier rules: inshort: ⊦ i ∈short ↔ ~32768 ≤ i ∧ i ≤ 32767;