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Proof step 2 from proof div-inshort (previous step)

⊦ s2i(sho1) = 0, ~32768 ≤ s2i(sho0) / s2i(sho1) ∧ s2i(sho0) / s2i(sho1) ≤ 32767 ↔ s2i(sho1) ≠ ~1 ∨ s2i(sho0) ≠ ~32768

User applied rule cut formula

And obtained the following new goals

Proof step 3:
s2i(sho1) ≠ ~1 ⊦ s2i(sho1) = 0, ~32768 ≤ s2i(sho0) / s2i(sho1) ∧ s2i(sho0) / s2i(sho1) ≤ 32767 ↔ s2i(sho1) ≠ ~1 ∨ s2i(sho0) ≠ ~32768
Proof step 51:
⊦ s2i(sho1) ≠ ~1, s2i(sho1) = 0, ~32768 ≤ s2i(sho0) / s2i(sho1) ∧ s2i(sho0) / s2i(sho1) ≤ 32767 ↔ s2i(sho1) ≠ ~1 ∨ s2i(sho0) ≠ ~32768

Rule argument

fma: s2i(sho1) ≠ ~1

Additional information

Used formulas: s2i(sho1) ≠ ~1