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Proof step 10 from proof div-inshort (previous step)

0 < s2i(sho1), s2i(sho0) / s2i(sho1) < ~32768, s2i(sho0) / s2i(sho1) < 0 ⊦ s2i(sho1) = 0, s2i(sho1) = ~1, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0, ¬ 0 ≤ s2i(sho0) ∧ ¬ 0 < s2i(sho1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1