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Proof step 9 from proof div-inshort (previous step)

s2i(sho0) / s2i(sho1) < ~32768, s2i(sho0) / s2i(sho1) < 0 ⊦ s2i(sho1) = 0, s2i(sho1) = ~1, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0, ¬ 0 ≤ s2i(sho0) ∧ ¬ 0 < s2i(sho1)

User applied rule cut formula

And obtained the following new goals

Proof step 10:
0 < s2i(sho1), s2i(sho0) / s2i(sho1) < ~32768, s2i(sho0) / s2i(sho1) < 0 ⊦ s2i(sho1) = 0, s2i(sho1) = ~1, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0, ¬ 0 ≤ s2i(sho0) ∧ ¬ 0 < s2i(sho1)
Proof step 18:
s2i(sho0) / s2i(sho1) < ~32768, s2i(sho0) / s2i(sho1) < 0 ⊦ 0 < s2i(sho1), s2i(sho1) = 0, s2i(sho1) = ~1, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0, ¬ 0 ≤ s2i(sho0) ∧ ¬ 0 < s2i(sho1)

Rule argument

fma: 0 < s2i(sho1)

Additional information

Used formulas: 0 < s2i(sho1)