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Proof step 8 from proof div-inshort (previous step)

¬(0 ≤ s2i(sho0) ∧ 0 < s2i(sho1) ∨ s2i(sho0) < 0 ∧ s2i(sho1) < 0), s2i(sho0) / s2i(sho1) < ~32768, s2i(sho0) / s2i(sho1) < 0 ⊦ s2i(sho1) = 0, s2i(sho1) = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
s2i(sho0) / s2i(sho1) < ~32768, s2i(sho0) / s2i(sho1) < 0 ⊦ s2i(sho1) = 0, s2i(sho1) = ~1, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0, ¬ 0 ≤ s2i(sho0) ∧ ¬ 0 < s2i(sho1)

Rule argument

Additional information

Used simplifier rules: lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs