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Proof step 31 from proof div-inshort (previous step)

0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1) ⊦ s2i(sho1) = ~1, s2i(sho1) = 0, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0

User applied rule cut formula

And obtained the following new goals

Proof step 32:
s2i(sho0) < 0, 0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1) ⊦ s2i(sho1) = ~1, s2i(sho1) = 0, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0
Proof step 50:
0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1) ⊦ s2i(sho0) < 0, s2i(sho1) = ~1, s2i(sho1) = 0, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0

Rule argument

fma: s2i(sho0) < 0

Additional information

Used formulas: s2i(sho0) < 0