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Proof step 32 from proof div-inshort (previous step)

s2i(sho0) < 0, 0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1) ⊦ s2i(sho1) = ~1, s2i(sho1) = 0, ¬ s2i(sho0) < 0 ∧ ¬ s2i(sho1) < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs