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Proof step 33 from proof div-inshort (previous step)

0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1), s2i(sho0) < 0 ⊦ s2i(sho1) = ~1, s2i(sho1) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 34:
⊦ i < 0 ∧ 0 < j → ¬ 0 < i / j
Proof step 35:
¬(s2i(sho0) < 0 ∧ 0 < s2i(sho1)), 0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1), s2i(sho0) < 0 ⊦ s2i(sho1) = ~1, s2i(sho1) = 0

Rule argument

spec: int-div inst: name: div-zero-ngr seq: ⊦ i < 0 ∧ 0 < j → ¬ 0 < i / j subst: [j, i] → [s2i(sho1), s2i(sho0)] flags: rewrite

Additional information

Used terms: s2i(sho1), s2i(sho0)