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Proof step 35 from proof div-inshort (previous step)

¬(s2i(sho0) < 0 ∧ 0 < s2i(sho1)), 0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1), s2i(sho0) < 0 ⊦ s2i(sho1) = ~1, s2i(sho1) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%lels-03: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs