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Proof step 36 from proof div-inshort (previous step)

0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1), s2i(sho0) < 0, s2i(sho1) < 0 ⊦ s2i(sho1) = ~1, s2i(sho1) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 37:
⊦ ¬ i0 < abs(i) ∧ i ≤ 0 ∧ j < 0 → ¬ i0 < i / j
Proof step 38:
¬(¬ 32767 < abs(s2i(sho0)) ∧ s2i(sho0) ≤ 0 ∧ s2i(sho1) < 0), 0 < s2i(sho0) / s2i(sho1), 32767 < s2i(sho0) / s2i(sho1), s2i(sho0) < 0, s2i(sho1) < 0 ⊦ s2i(sho1) = ~1, s2i(sho1) = 0

Rule argument

spec: int-div inst: name: div-nls-01 seq: ⊦ ¬ i0 < abs(i) ∧ i ≤ 0 ∧ j < 0 → ¬ i0 < i / j subst: [j, i, i0] → [s2i(sho1), s2i(sho0), 32767] flags: rewrite

Additional information

Used terms: s2i(sho1), s2i(sho0), 32767