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Proof step 52 from proof div-inshort (previous step)

s2i(sho1) = ~1 ⊦ ~32767 ≤ s2i(sho0) ↔ s2i(sho0) ≠ ~32768

User applied rule case distinction

And obtained the following new goals

Proof step 53:
s2i(sho0) ≠ ~32768, s2i(sho1) = ~1 ⊦ ~32767 ≤ s2i(sho0)

Rule argument

pos: right 1

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs