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Proof step 53 from proof div-inshort (previous step)

s2i(sho0) ≠ ~32768, s2i(sho1) = ~1 ⊦ ~32767 ≤ s2i(sho0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 54:
s2i(sho1) = ~1, s2i(sho0) < ~32767, s2i(sho0) < 0 ⊦ s2i(sho0) = ~32768

Rule argument

Additional information

Used simplifier rules: numlsf: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward) from specification int-basic1%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs