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Proof step 3 from proof fits-law-add (previous step)

¬(~32768 ≤ b2i(by1) + b2i(by2) ∧ b2i(by1) + b2i(by2) < 32768) ⊦ b2i(by1) + b2i(by2) = s2i(i2s(b2i(by1) + b2i(by2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ ¬ i ≤ j ↔ j < i;