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Proof step 4 from proof fits-law-add (previous step)

⊦ b2i(by1) + b2i(by2) = s2i(i2s(b2i(by1) + b2i(by2))), ¬ b2i(by1) + b2i(by2) < ~32768 ∧ ¬ 32768 ≤ b2i(by1) + b2i(by2)

User applied rule case distinction

And obtained the following new goals

Proof step 5:
⊦ ¬ b2i(by1) + b2i(by2) < ~32768, b2i(by1) + b2i(by2) = s2i(i2s(b2i(by1) + b2i(by2)))
Proof step 9:
⊦ ¬ 32768 ≤ b2i(by1) + b2i(by2), b2i(by1) + b2i(by2) = s2i(i2s(b2i(by1) + b2i(by2)))

Rule argument

pos: right 2

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