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Proof step 5 from proof fits-law-add (previous step)

⊦ ¬ b2i(by1) + b2i(by2) < ~32768, b2i(by1) + b2i(by2) = s2i(i2s(b2i(by1) + b2i(by2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
b2i(by1) + b2i(by2) < ~32768, b2i(by1) + b2i(by2) < 0 ⊦ b2i(by1) + b2i(by2) = s2i(i2s(b2i(by1) + b2i(by2)))

Rule argument

Additional information

Used simplifier rules: ⊦ i + j + i0 = (i + j) + i0;% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)% ⊦ i + j = j + i;