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Proof step 10 from proof fits-law-bor-02 (previous step)

¬(bcompl(s2i(sho1)) ∈short ∧ bcompl(s2i(sho2)) ∈short) ⊦ bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))))), s2i(i2s(band(bcompl(s2i(sho1)), bcompl(s2i(sho2))))) = band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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