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Proof step 11 from proof fits-law-bor-02 (previous step)

⊦ s2i(i2s(band(bcompl(s2i(sho1)), bcompl(s2i(sho2))))) = band(bcompl(s2i(sho1)), bcompl(s2i(sho2))), bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))))), bcompl(s2i(sho1)) ∈short ∧ bcompl(s2i(sho2)) ∈short

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ i ∈short ↔ s2i(i2s(i)) = i
Proof step 13:
⊦ s2i(i2s(band(bcompl(s2i(sho1)), bcompl(s2i(sho2))))) = band(bcompl(s2i(sho1)), bcompl(s2i(sho2))), bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))))), s2i(i2s(bcompl(s2i(sho1)))) = bcompl(s2i(sho1)) ∧ bcompl(s2i(sho2)) ∈short

Rule argument

name: inshort-sis rotate: F subst: [i] → [bcompl(s2i(sho1))]

Additional information

Used terms: bcompl(s2i(sho1))