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Proof step 3 from proof fits-law-bor-02 (previous step)

⊦ bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2))))))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i ∈short → s2i(i2s(bcompl(i))) = bcompl(i)
Proof step 5:
¬ band(bcompl(s2i(sho1)), bcompl(s2i(sho2))) ∈short ⊦ bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2))))))

Rule argument

name: bcompl-sis rotate: F subst: [i] → [band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))]

Additional information

Used terms: band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))