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Proof step 5 from proof fits-law-bor-02 (previous step)

¬ band(bcompl(s2i(sho1)), bcompl(s2i(sho2))) ∈short ⊦ bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2))))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))) = s2i(i2s(bcompl(band(bcompl(s2i(sho1)), bcompl(s2i(sho2)))))), band(bcompl(s2i(sho1)), bcompl(s2i(sho2))) ∈short

Proof step 5 from proof fits-law-bor-02 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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