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Proof step 1 from proof fits-law-bor (conclusion)

⊦ bor(b2i(by1), b2i(by2)) = b2i(i2b(bor(b2i(by1), b2i(by2))))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ bor(i, j) = bcompl(band(bcompl(i), bcompl(j)))
Proof step 3:
⊦ bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2)))) = b2i(i2b(bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2))))))

Rule argument

seq: ⊦ bor(i, j) = bcompl(band(bcompl(i), bcompl(j))) subst: [j, i] → [b2i(by2), b2i(by1)] rotate: F spec: intops inst: name: bor-notAndNot

Additional information

Used terms: b2i(by2), b2i(by1)