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Proof step 3 from proof fits-law-bor (previous step)

⊦ bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2)))) = b2i(i2b(bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2))))))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i ∈byte → b2i(i2b(bcompl(i))) = bcompl(i)
Proof step 5:
¬ band(bcompl(b2i(by1)), bcompl(b2i(by2))) ∈byte ⊦ bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2)))) = b2i(i2b(bcompl(band(bcompl(b2i(by1)), bcompl(b2i(by2))))))

Rule argument

name: bcompl-bib rotate: F subst: [i] → [band(bcompl(b2i(by1)), bcompl(b2i(by2)))]

Additional information

Used terms: band(bcompl(b2i(by1)), bcompl(b2i(by2)))