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Proof step 5 from proof fits-law-bxor-02 (previous step)

¬(band(s2i(sho1), bcompl(s2i(sho2))) ∈short ∧ band(bcompl(s2i(sho1)), s2i(sho2)) ∈short) ⊦ bor(band(s2i(sho1), bcompl(s2i(sho2))), band(bcompl(s2i(sho1)), s2i(sho2))) = s2i(i2s(bor(band(s2i(sho1), bcompl(s2i(sho2))), band(bcompl(s2i(sho1)), s2i(sho2)))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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